# Line slope calculator 4x-5y=4

**Straight line given by points A[1; 0] and B[6; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.8x-0.8

**Canonical form of the line equation:**4x-5y-4 = 0

**Parametric form of the line equation:**

x = 5t+1

y = 4t ; t ∈ R

**Slope:**m = 0.8

**Slope angle of line: φ =**38°39'35″ = 0.6747 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = -0.8

**Distance line from the origin:**d

_{0}= 0.6247

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; 4)

**Normal vector: n =**(4; -5)

**Midpoint of the segment AB: M =**[3.5; 2]

**Perpendicular Bisector equation:**5x+4y-25.5 = 0

**Vector OA = (1; 0) ; |OA| = 1**

**Vector OB = (6; 4) ; |OB| = 7.2111**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**